x^2-95x-800=0

Solution for x^2-95x-800=0 equation:

x^2-95x-800=0

a = 1; b = -95; c = -800;
Δ = b2-4ac
Δ = -952-4·1·(-800)
Δ = 12225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12225}=\sqrt{25*489}=\sqrt{25}*\sqrt{489}=5\sqrt{489}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{489}}{2*1}=\frac{95-5\sqrt{489}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{489}}{2*1}=\frac{95+5\sqrt{489}}{2}
$